Resposta :

Energia        Potencial          Elástica        =    K X²/2



40  N /m       X   0, 0 4 m  =  16      X    0, 0 4 m     = 0064   
÷    2   =  0,032J


EPE    =   0,032J
 

BONS     ESTUDOS

[tex]\Large{\begin{array}{l}\tt E_p=\dfrac{k\cdot x^2}{2}\\\\\tt E_p=\dfrac{40\cdot(0{,}04)^2}{2}\\\\\tt E_p=\dfrac{40\cdot0{,}0016}{2}\\\\\tt E_p=\dfrac{0{,}064}{2}\\\\\boxed{\boxed{\tt E_p=0{,}032\,J}}\end{array}}[/tex]

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