Resposta :
x + 2 y = 3(-3) => -3x -6y = -9
2 x +3 y =5(2) 4x +6y= 10
x = 1
x + 2y = 3
1 2y = 3 ==> 2y = 3 -1 ==> 2y = 2 ==> y = 1
o ponto de interseção das retas x + 2y=3 e 2x+3y-5=0 é: (1,1) (1,2) (-1,1) (2,1) (1,-1)
x + 2 y = 3(-3) => -3x -6y = -9
2 x +3 y =5(2) 4x +6y= 10
x = 1
x + 2y = 3
1 2y = 3 ==> 2y = 3 -1 ==> 2y = 2 ==> y = 1