2ab- [3b-(2a +3b-ab)]
(a/2 +2x +1) - (x - 3a/4 - 2/5)
Olá, ragi.
[tex]2ab- [3b-(2a +3b-ab)]=2ab-[3b-2a-3b+ab]=[/tex]
[tex]=2ab+2a-ab=a(2b+2-b)=a(b+2)[/tex]
[tex](\frac{a}2 +2x +1) - (x - \frac{3a}4 - \frac25)=\frac{a}2 +2x +1-x+\frac{3a}4 +\frac25=[/tex]
[tex]=\frac{2a+3a}4+x+\frac{5+2}5=\frac54 a + x + \frac75[/tex]
Regi,
2ab- [3b-(2a +3b-ab)]
2ab - [3b -2a - 3b + ab]
2ab - [- 2a + ab]
2ab + 2a - ab
ab + 2a
a(b + 2) RESULTADO FINAL
(a/2 +2x +1) - (x - 3a/4 - 2/5)
a/2 + 2x + 1 - x + 3a/4 + 2/5
a(1/2 + 3/4) + x + (1 + 2/5)
a(2/4 + 3/4) + x + (5/5 + 2/5)
a(5/4) + x + (7/5)
5/4a + x + 7/5 RESULTADO FINAL
