Resposta :
[tex]\frac{3\sqrt2}{5\sqrt3+4\sqrt2} \cdot \frac{5\sqrt3-4\sqrt2}{5\sqrt3-4\sqrt2}= [/tex]
[tex]\frac{3\sqrt2}{5\sqrt3+4\sqrt2} \cdot \frac{5\sqrt3-4\sqrt2}{5\sqrt3-4\sqrt2}=\frac{15\sqrt6-24}{75-32}=\frac{15\sqrt6-24}{43}[/tex]
como resolvo ? (3√2)/(5√3+4√2)
[tex]\frac{3\sqrt2}{5\sqrt3+4\sqrt2} \cdot \frac{5\sqrt3-4\sqrt2}{5\sqrt3-4\sqrt2}= [/tex]
[tex]\frac{3\sqrt2}{5\sqrt3+4\sqrt2} \cdot \frac{5\sqrt3-4\sqrt2}{5\sqrt3-4\sqrt2}=\frac{15\sqrt6-24}{75-32}=\frac{15\sqrt6-24}{43}[/tex]