Resposta :
f(1) = 3 e f(n+1) = 5.f(n) + 1.
f(0) =
f(0+1) = 5.f(0) + 1
f(1) = 5.f(0) + 1
3 = 5.f(0) + 1
3-1 = 5f(0)
f(0) = 2/5
f(2)
f(1+1) = 5.f(1) + 1
f(2)=5.3 + 1
f(2)=16
f(3).
f(2+1) = 5.f(2) + 1
f(3)=5.16 + 1
f(3)=33