Resposta :
4c =c(1+0,02)^t
4= 1,02^t aplicandolog. temos
log 4 = log(1,02)^t
log4 =t log1,02
t = log4
log1,02
t = log 2^2 - log 102
100
t=2log2 -( log102 - log 100)
t= 2log2 - log102 +log 10^2
t = 2.log2 - log102 +2log10
t = 2.(0,3010) - 2,0086 +2
t=0,6020 - 2,0086 +2
t= 0,5934