Resposta :

3478elc

A = 1/2 |y1(x2 − x3) + y2(x3 − x1) + y3(x1 − x2)|

 

aA=1/2 / 12+20+0/

 

 

A= 1/2. 32 

 

A= 16

 

 

 A (-3,-3), B (-2,4) e C (2,0)


|y1(x2 − x3) = -3(-2-2) = -3(-4) =12

 

 y2(x3 − x1)= 4(2-(-3)) = 4 (2+3) = 4.5 = 20 

 

 y3(x1 − x2)| = 0(-3-(-2))=0

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