quando misturamos 1.0kg de agua (calor especifico sensivel1.0cal/g*C)a 70*C com 2.0kg de agua a 10*C ,obtemos 3.0kg de agua a q temperatura responde ai por favor
Q1+Q2=0
Q=m*c*/\t
1000 * 1 * (tf-70) + 2000*1* (tf-10) = 0
1000tf - 70.000 + 2000tf - 20.000 = 0
3000tf - 90.000 = 0
3000tf = 90.000
tf= 90.000/3000
tf=30°C
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A temperatura final dos 3kg de água é 30°C
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