Como resolver x² + 2x - 35 =0 e (x-2)(x+5)=0
х ^2 + 2x - 35 = 0
Находим дискриминат
D = b^2 - 4ac = 4 - 4 * 1 * (-35) = 4 + 140 = 144
x1 = [tex]\frac{-b - \sqrt{D}}{2a} = \frac{-2 - \sqrt{144}}{2} = \frac{-14}{2} = -7[/tex]
x2 = [tex]\frac{-b - \sqrt{D}}{2a} = \frac{-2 + \sqrt{144}}{2} = \frac{10}{2} = 5[/tex]