Resposta :
x^2 - 5x = 104
b^2 - 4.a.c
-5² - 4.1.-104
25 + 416
= v441
=21
5+21 = 26
26/2 = 13 anos
b^2 - 4.a.c
-5² - 4.1.-104
25 + 416
= v441
=21
5+21 = 26
26/2 = 13 anos
x^2 - 5x = 104
x^2 - 5x- 104= 0
delta = (-5)^2 - 4.1.(-104)= 25 + 416 = 441
x= 5 +/- V441 ==> x= 5 +/- 21 ==> x1= 5+21= 13 ; x2 = 5 - 21 = - 8
2.1 2 2 2
x^2 - 5x- 104= 0
delta = (-5)^2 - 4.1.(-104)= 25 + 416 = 441
x= 5 +/- V441 ==> x= 5 +/- 21 ==> x1= 5+21= 13 ; x2 = 5 - 21 = - 8
2.1 2 2 2