Resposta :
a)
3 (x-1)= 2 - 2 (2x-1) + 5
3x - 3 = 2 - 4x +2 + 5
3x + 4x = 2 + 2 + 5 + 3
7x = 12
x= 12/7
b)
[tex]\frac{x-2}{2} - \frac{x+1}{4} = \frac{x-3}{8} - 1 \\ 4(x-2)-2(x+1)=x-3-8 \\ 4x-8-2x-2=x-11 \\ 4x-2x-x=-11+8+2 \\ x=-1[/tex]
3 (x-1)= 2 - 2 (2x-1) + 5
3x - 3 = 2 - 4x +2 + 5
3x + 4x = 2 + 2 + 5 + 3
7x = 12
x= 12/7
b)
[tex]\frac{x-2}{2} - \frac{x+1}{4} = \frac{x-3}{8} - 1 \\ 4(x-2)-2(x+1)=x-3-8 \\ 4x-8-2x-2=x-11 \\ 4x-2x-x=-11+8+2 \\ x=-1[/tex]