Resposta :
f(x)=x²+2x-1
a)f(0) = 0²+2.0-1 = -1
b)f(1)= 1²+2.1-1 = 2
c)f(2)-f(-2) = 2²+2.2-1 - [(-2)²+2(-2)-1]=7+1=8
a)f(0) = 0²+2.0-1 = -1
b)f(1)= 1²+2.1-1 = 2
c)f(2)-f(-2) = 2²+2.2-1 - [(-2)²+2(-2)-1]=7+1=8
a)f(x)=x²+2x-1
f(0)=0+2.0-1
f(0)=-1
b)f(x)=x²+2x-1
f(1)=1²+2.1-1
f(1)=1+2-1
f(1)=2
c)f(x)=x²+2x-1
f(2)=2²+2.2-1
f(2)=4+4-1
f(2)=7
f(x)=x²+2x-1
f(-2)=-2²+2.-2-1
f(-2)=4-4-1
f(-2)=-1
f(2)-f(-2)
7-(-1)
7+1
8
f(0)=0+2.0-1
f(0)=-1
b)f(x)=x²+2x-1
f(1)=1²+2.1-1
f(1)=1+2-1
f(1)=2
c)f(x)=x²+2x-1
f(2)=2²+2.2-1
f(2)=4+4-1
f(2)=7
f(x)=x²+2x-1
f(-2)=-2²+2.-2-1
f(-2)=4-4-1
f(-2)=-1
f(2)-f(-2)
7-(-1)
7+1
8