Resposta :

MATHSPHIS
[tex]\frac{(\frac{x{^2}^3}{(x^2)^3})^{-2}}{{x^{2}}^4 \cdot x^{-16}}= \\ \\ \frac{(\frac{x^8}{x^6})^{-2}}{x^{16}\cdot x^{-16}}=\frac{(x^2)^{-2}}{1}= \\ \\ x^{-4}=\frac{1}{x^4}=(\frac{1}{x})^4[/tex]

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