Resposta :
Supondo que a taxa é mensal:
M=C(1+i)^t
[tex]M=C(1+i)^t \\ M=580,22(1+0,045)^7 \\ M=580,22.(1,045)^7 \\ M=580,22. \\ M=580. 1,36 \\ M=789,30 \\ j=M-C \\ j=789,30-580,22 \\ j=209,09[/tex]
M=C(1+i)^t
[tex]M=C(1+i)^t \\ M=580,22(1+0,045)^7 \\ M=580,22.(1,045)^7 \\ M=580,22. \\ M=580. 1,36 \\ M=789,30 \\ j=M-C \\ j=789,30-580,22 \\ j=209,09[/tex]