Resposta :
Maria,
log128/8 = 3 x
log 128 - log 8 = 3x
x = (log 128 - log8) / 3
x = (2,11 - 0,90) / 3
x = 1,21 / 3
x = 0,40
Ok?
log128/8 = 3 x. Log128-log8=3x
x = (log 128 - log8) / 3. X=(2,11-0,90)/3
x = 1,21 / 3. X =0,40