Resposta :

 

 Maria,

 

log128/8 = 3 x

 

log 128 - log 8 = 3x

 

x = (log 128 - log8) / 3

 

x = (2,11 - 0,90) / 3

 

x = 1,21 / 3

 

x = 0,40

 

Ok?

 

 

 

log128/8 = 3 x.     Log128-log8=3x

 

 

x = (log 128 - log8) / 3.    X=(2,11-0,90)/3

 

 

x = 1,21 / 3.   X =0,40

 

 

 

Outras perguntas