Resposta :

[tex]f(x)=0,8x^4+1/3x^3 \sqrt{x}+cos x+e^x+1n(x)+1/x^3,para x=1\\ f(1)=0,8(1)^4+1/3(1)^3 \sqrt{1}+cos 1+e^1+1n(1)+1/1^3\\ f(1)=0,8+1/3+cos 1+e^1+0+1\\ f(1)=9/5+1/3+cos1+e\\ f(1)=\frac{27+5}{15}+cos1+e\\ \\ f(1)=\frac{32}{15}+cos1+e[/tex]

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