Resposta :

MATHSPHIS
[tex] \frac{(x+2)!}{4!(x-2)!}=11.\frac{x!}{2!(x-2)!}= \\ \\ \frac{(x+2)!}{4.3}=11x! \\ \\ (x+2)!=132x! \\ \\ (x+2)(x+1)=132 \\ \\ x^2+3x-130=0 \\ \\ \boxed{x=10} [/tex]

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