Resposta :
Seja [tex]\text{q}=\dfrac{40\text{x}^2-20\text{x}-3\text{ax}}{-10\text{x}}[/tex].
Note que, [tex]\dfrac{40\text{x}^2}{-10\text{x}}=-4\text{x}[/tex].
Depois disso, vemos que, [tex]\dfrac{-20\text{x}}{-10\text{x}}=2[/tex].
Logo, [tex]\text{q}=\dfrac{40\text{x}^2-20\text{x}-3\text{ax}}{-10\text{x}}=-4\text{x}+2[/tex].
Escrevemos assim: [tex]40\text{x}^2-20\text{x}-3\text{ax}=(-10\text{x})\cdot\text{q}-3\text{ax}[/tex]
Note que, [tex]\dfrac{40\text{x}^2}{-10\text{x}}=-4\text{x}[/tex].
Depois disso, vemos que, [tex]\dfrac{-20\text{x}}{-10\text{x}}=2[/tex].
Logo, [tex]\text{q}=\dfrac{40\text{x}^2-20\text{x}-3\text{ax}}{-10\text{x}}=-4\text{x}+2[/tex].
Escrevemos assim: [tex]40\text{x}^2-20\text{x}-3\text{ax}=(-10\text{x})\cdot\text{q}-3\text{ax}[/tex]