Resposta :

3478elc

a) f(g(x)) =  raizcubica ( 1- (1-x3) = raiz cúbica( 1-1+x3) =  raiz cúbica x3 = x

 

 

b) 1-(raiz cúbica(1-x))^3 = 1-(1-x)  => 1 - 1 +x => x

 

 

são iguais

 

e fui.

pemela

a) f(g(x)) =  raizcubica ( 1- (1-x3) = raiz cúbica( 1-1+x3) =  raiz cúbica x3 = x

 

 

b) 1-(raiz cúbica(1-x))^3 = 1-(1-x)  => 1 - 1 +x => x

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