Resposta :
comprimento = distância percorrida
1,2 cm = 0,012 m = 1,2 . 10^-2
[tex]V^{2} = Vo^{2} + 2aS (6,8.10^{6})^{2} = (2,5.10^{5})^{2} + 2.a.1,2.10^{-2} 2.a.1,2.10^{-2} = \frac{46,24.10^{12} }{6,25.10^{10}} [/tex]
a = [tex]a= \frac{7,3984.10^{2}}{2,4.10^{-2}} = 3,08.10^{4} m/s^{2} [/tex]
1,2 cm = 0,012 m = 1,2 . 10^-2
[tex]V^{2} = Vo^{2} + 2aS (6,8.10^{6})^{2} = (2,5.10^{5})^{2} + 2.a.1,2.10^{-2} 2.a.1,2.10^{-2} = \frac{46,24.10^{12} }{6,25.10^{10}} [/tex]
a = [tex]a= \frac{7,3984.10^{2}}{2,4.10^{-2}} = 3,08.10^{4} m/s^{2} [/tex]