Resposta :
[tex]a)(\frac{1}{81})^{2x}=\frac{1}{27} \\
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(\frac{1}{3})^{8x}=(\frac{1}{3})^3 \rightarrow 8x=3 \rightarrow x=\frac{3}{8} \\
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b)(\frac{9}{25})=(\frac{3}{5})^{3x} \\
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(\frac{3}{5})^2=(\frac{3}{5})^{3x} \rightarrow 3x=2 \rightarrow x=\frac{2}{3} \\
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c) (\frac{4}{5})^{2x}=1 \\
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(\frac{4}{5})^{2x}=(\frac{4}{5})^0 \rightarrow 2x=0 \rightarrow x=0 \\
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d)(\frac{2}{3})^x=\frac{9}{4} \\
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(\frac{2}{3})x=(\frac{2}{3})^{-2} \rightarrow 2x=-2 \rightarrow x=-1[/tex]
[tex]e)( \sqrt{\frac{125}{27}})^{\frac{x}{2} =\frac{81}{625} \\ (\frac{5}{3})^{\frac{x}{2}=(\frac{5}{3})^{-4} \rightarrow \frac{x}{2}=-4 \rightarrow x=-8[/tex]
[tex]e)( \sqrt{\frac{125}{27}})^{\frac{x}{2} =\frac{81}{625} \\ (\frac{5}{3})^{\frac{x}{2}=(\frac{5}{3})^{-4} \rightarrow \frac{x}{2}=-4 \rightarrow x=-8[/tex]