HelenaCarvalho
Respondido

1.Dados f(x) = log de (x+1) na base 3,g(x) = 4+log de x na base 2 e h(x) = log de 2x,determine :
a) f(2) b) g(2) c) h(5) d) h(50) e) g(1) f) f(0) g) f(26) h) g(raiz de2)

Resposta :

3478elc
 f(x) = log de (x+1) na base 3,
a) f(2) = log(2+1) = log3 = 1
f) f(0) =log(0+1) = log 1          3^x = 1 ==. 3^x = 3^0 ==> x = 0
f(26) = log(26+1) = log 27      3^x = 27 ==. 3^x = 3^3 ==> x = 3
g(x) = 4+log de x na base 2  
b) g(2) = 4 +log2 = 4+1 = 5
g(1)= 4+ log 1 = 4+ log 1 ==> 4 + 0 = 4          2^x = 1 ==. 2^x = 2^0 ==> x = 0 
 g(raiz de2)= 4+ logV2 = 4 + 1/2 = (8+1)/2 = 9/2        2^x =V2 ==>2^x = 2^1/2 ==>x = 1/2

h(x) = log de 2x,de
c) h(5) = log 2.5 = log10 = 1

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