Resposta :

MATHSPHIS
[tex]log_3{100}-log_3{18}-log_3{50} = x \\ log_3(\frac{\frac{100}{18}}{50})= x \\ log_3(\frac{100}{18}.\frac{1}{50})=x \\ log_3{\frac{1}{9}=x \rightarrow 3^x=3^{-2} \rightarrow x=-2 [/tex]

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