Resposta :

MATHSPHIS
[tex]x_V=\frac{-b}{2a} \\ \\ x_V=\frac{5}{6} \\ \\ y_V=\frac{-\Delta}{4a} \\ \\ y_V=\frac{-[(-5)^2-4.3.9]}{4.3}=\frac{-[25-108]}{12}=\frac{83}{12} \\ \\ x_V+y_V=\frac{5}{6}+\frac{83}{12}=\frac{10+83}{12}=\boxed{\frac{93}{12}}[/tex]

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