Resposta :
[tex]2000(1+k)^10=2400 \\
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(1+k)^{10}=\frac{2400}{2000} \\
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(1+k)^{10}=1,2 \\
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log(1+k)^{10}=log1,2 \\
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10.log(1+k)=log1,2 \\
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log (1+k)=\frac{log1,2}{10} \\
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1+k=10^{\frac{log1,2}{10}} \\
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\boxed{k=10^{\frac{log1,2}{10}}-1}[/tex]