Resposta :

3478elc



2x^2y^2 ( 1 + 2xy^2 - x^3y)
3



xy(4 - 3xy + 10x^2)
ArthurPDC
[tex]\dfrac{2x^2y^2}{3}+\dfrac{4x^3y^4}{3}-\dfrac{2x^5y^3}{3}=\dfrac{2x^2y^2+4x^3y^4-2x^5y^3}{3}=\dfrac{2x^2y^2(1+2xy^2-x^3y)}{3}\\\\ 4xy-3x^2y^2+10x^3y=xy(4-3xy+10x^2)[/tex]

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