[tex]\frac{\left(1-\frac{1}{2}\right)^2}{\frac{3}{4}}+\frac{\frac{1}{5}}{\left(1-\frac{4}{5}\right)^2}= \\
\\
\frac{\left(\frac{1}{2}\right)^2}{\frac{3}{4}}+\frac{\frac{1}{5}}{\left(\frac{1}{5}\right)^2} = \\
\\
\frac{\frac{1}{4}}{\frac{3}{4}}+\frac{\frac{1}{5}}{\frac{1}{25}}= \\
\\
\frac{1}{3}+5=\frac{16}{3}[/tex]
