Resposta :

x^2 - x - 12 = 0
a= 1, b= -1, c= -12
delta = b^2 - 4.a.c
delta = (-1)^2 - 4.1.(-12)
delta = 1 + 48
delta = 49
x = -b +_ raiz de delta / 2.a
x = -(-1) +_ 7 / 2
x = 1 +_ 7 / 2
x* = 1 - 7 / 2
x* = -6/2
x* = -3

x** = 1 + 7 / 2
x** = 8/2
x** = 4

S = { -3, 4 }

ESPERO TER AJUDADO!
AntoniLAD
[tex] x^{2} -x-12=0=
\Delta= b^{2} -4.a.c=
\Delta= 1^{2} -4.1(-12)=
\Delta=1+48=49
x^{1} =-1-+ \sqrt{49}/2 =-1+7/2=6/2=3
x^{2} =-1-+ \sqrt{49} /2=-1-7/2=-8/2=-4[/tex]

S={3,-4}

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