Resposta :
[tex]6! = 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 = \boxed{720}
\\\\
3!-2! = (3 \cdot 2 \cdot 1)-(2 \cdot 1) = 6-2 = \boxed{4}
\\\\
5 \cdot 3! = 5 \cdot (3 \cdot 2 \cdot 1) = 5 \cdot 6 = \boxed{30}
\\\\
7!+5! = (7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1) + (5 \cdot 4 \cdot 3 \cdot 2 \cdot 1) =
\\
= 5040+120 = \boxed{5160}[/tex]