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[tex]3 \sqrt{128} -4 \sqrt{50} +2 ^{3} \sqrt{128}-8 ^{3} \sqrt{2}como se calcula???
R:[tex]4 \sqrt{2} [/tex]

Resposta :

ittalo25
[tex]3 \sqrt{128} - 4 \sqrt{50} + 2^3 \sqrt{128} - 8^3 \sqrt{2} = 3.8 \sqrt{2} - 4.5 \sqrt{2} + 8.8 \sqrt{2} - 512 \sqrt{2} = 24 \sqrt{2} - 20 \sqrt{2} + 64 \sqrt{2} - 512 \sqrt{2} = 4 \sqrt{2} - 448 \sqrt{2} = -484\sqrt{2} =[/tex]

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