Resposta :

GabrielAw9
a)

Seno de 30 = x/y

1/2 = x/y
2x=y


b)

Seno de 30 = 10/y
1/2 = 10/y
y=20

Tangente de 30 = 10/x

√3 / 3 = 10/x
x=30√3

c)

Seno de 60 = y/12

√3/2 = y/12
2y=12√3
y=12√3/2
y=6√3

Cosseno de 60 = x/12
1/2 = x/12

2x=12
x=12/2
x=6

d)
Tangente de 45 = x/8√2
1 = x/8√2
x=8√2

Seno de 45 = 8√2 / y

√2 /2 = 8√2 / y
√2y=16√2
y=16√2 / √2
y=16

e)

tangente de 60 = y/√3
√3 = y /√3
y=√9
y=3

Cosseno de 60 = √3 / x

1/2 = √3/x
x=2√3
CyberKirito

a)

[tex]\sin(30\degree)=\frac{x}{y}\\\frac{1}{2}=\frac{x}{y}\\y=2x[/tex]

b)

[tex]\sin(30\degree)=\frac{10}{y}\\frac{1}{2}=\frac{10}{y}\\y=2.10=20[/tex]

c)

[tex]\cos(60\degree)=\frac{x}{12}\\\frac{1}{2}=\frac{x}{12}\\2x=12\\x=\frac{12}{2}=6[/tex]

[tex]\tan(60\degree)=\frac{y}{6}\\\sqrt{3}=\frac{y}{6}\\y=6\sqrt{3}[/tex]

d)

[tex]\tan(45\degree)=\frac{x}{8\sqrt{2}}\\1=frac{x}{8\sqrt{2}}\\x=8\sqrt{2}[/tex]

[tex]\sin(45\degree)=\frac{8\sqrt{2}}{y}\\\frac{\cancel{\sqrt{2}}}{2}=\frac{8\cancel{\sqrt{2}}}{y}[/tex]

[tex]y=8.2=16[/tex]

e)

[tex]\tan(60\degree)=\frac{y}{\sqrt{3}}\\\sqrt{3}=\frac{y}{\sqrt{3}}[/tex]

[tex]y=\sqrt{3}.\sqrt{3}=3[/tex]

[tex]\cos(60\degree)=\frac{\sqrt{3}}{x}\\\frac{1}{2}=\frac{\sqrt{3}}{x}[/tex]

[tex]x=2\sqrt{3}[/tex]

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