A) [tex] \frac{3x}{x-4} = \frac{3x+2}{x} <=> \frac{3x^{2} }{ x^{2}-4x } = \frac{3x ^{2} -10x-8}{ x^{2}-4x } [/tex] <=>
<=> 3[tex] x^{2} -3 x^{2} = -10x - 8[/tex] <=> 10x = 8 <=> x = 8/10 <=> x = 4/5
B) [tex] \frac{5}{y^{2}-9 } = \frac{-3y+9}{y ^{2}-9 } [/tex] <=>
5 = -3y + 9 <=>
<=> 5 - 9 = -3y <=>
y = 4/3
