Resposta :
Basta substitui o valor fornecido na fórmula
9.(K-273) = 5.(TF-32)
9( 400 -273) = 5TF - 160
9( 127 ) = 5TF - 160
1143 + 160 = 5TF
1303 = 5TF
TF = 1303 / 5
TF = 260,6 °F
9.(K-273) = 5.(TF-32)
9( 400 -273) = 5TF - 160
9( 127 ) = 5TF - 160
1143 + 160 = 5TF
1303 = 5TF
TF = 1303 / 5
TF = 260,6 °F