Resposta :

eluciamonteiro
 x2+x-12=0

Coeficientes:
a= 1     b= +1       c= -12

▲= b² -4.a.c
▲=(1)² -4.(1).(-12)
▲=1 +48
▲= 49

x= (-b ± √▲)
        2.a

x= [-(+1) ± √49]
        2.1

x= [-1 ± 7]
          2

x'=[-1+7] = +6  = 3    
       2         2

x"=[-1-7] = -8 = -4
        2        2

S{-4 ; 3}
 x2+x-12=0
Coeficientes:
a= 1  
b= 1
c= -12
Fórmula do Δ---> Δ=b²-4.a.c
Δ=1²-4.1.(-12)
Δ=1+48
Δ=49
Fórmula de Bhaskara ----> [tex]x= \frac{-b+- \sqrt{\Delta} }{2.a} [/tex]
[tex]x= \frac{-1+- \sqrt{49} }{2.1} \\\\ x= \frac{-1+-7}{2} \\\\ x'= \frac{-1+7}{2}\\\\ x'= \frac{6}{2}\\\\ x'=3\\\\ x"= \frac{-1-7}{2}\\\\ x"= \frac{-8}{2}\\\\ x"=-4\\\\ V=\{3,-4\} [/tex]

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