[tex]S = log_{2} 8 + log_{3} \frac{1}{9} + log_{5} \sqrt{5} [/tex]
[tex] log_{2} 8 -> 2^{X} = 2^{3} -> x= 3 [/tex]
[tex] log_{3} \frac{1}{9} -> 3^{x} = 3^{-2} -> x= -2 [/tex]
[tex] log_{5} \sqrt{5} -> 5^{x} = 5^{ \frac{1}{2} } -> x= \frac{1}{2} [/tex]
[tex]S = 3 + (-2) + \frac{1}{2} [/tex]
[tex]S = 1 + \frac{1}{2} [/tex]
[tex]S = \frac{3}{2} [/tex]
Espero ter ajudado ((:
