Resposta :
f(x) = y = x²-x
f(1) = 1²-1 = 1-1 = 0
f(-1) = (-1)²-(-1) = 1+1 = 2
f(3) = 3²-3 = 9-3 = 6
f(0) = 0²-0 = 0
f(1) + 3f(-1) - 5f(3) + f(0) =
0 + 3.2 - 5.6 + 0 =
6 - 30 = -24
Dada a função F(x)=y=x2-x, com xEr e ER calcule: F(1)+3f(-1)-5f(3)+f(0)
f(x) = y = x²-x
f(1) = 1²-1 = 1-1 = 0
f(-1) = (-1)²-(-1) = 1+1 = 2
f(3) = 3²-3 = 9-3 = 6
f(0) = 0²-0 = 0
f(1) + 3f(-1) - 5f(3) + f(0) =
0 + 3.2 - 5.6 + 0 =
6 - 30 = -24