Resposta :
Temos que:
[tex]\text{x}^2-\dfrac{\text{x}}{2}=\text{x}-\text{x}-\dfrac{\text{x}^2}{3}[/tex]
[tex]6\text{x}^2-3\text{x}=2\text{x}^2[/tex]
[tex]4\text{x}^2-3\text{x}=0[/tex]
[tex]\text{x}\cdot(4\text{x}-3)=0[/tex]
Logo, as raízes são:
[tex]\text{x}'=0[/tex]
[tex]\text{x}''=\dfrac{3}{4}[/tex]