Resposta :
28,48|2>>>>> diividisse pelo menornumero primo
14,24|2>>>>>quantas vezes necessarias
7,12 |2
7,6 | 2
7,3 |3
7, 1 | 7
1,1>>>>agora mutiplicasse só os ptimos que dividiram os dois numerosno caso 2*2=4
ou seja o mdc de 28 e 48 e 4
tente fazer os outros!!!!
Vlw
a) [tex]\text{mdc}(48, 28)[/tex].
[tex]\text{mdc}(48, 28)=\text{mdc}(28, 48-28)=\text{mdc}(28, 20)=\text{mdc}(20, 28-20)=\text{mdc}(20, 8)[/tex]
[tex]=\text{mdc}(8, 20-8)=\text{mdc}(8, 12)=\text{mdc}(8, 12-8)=\text{mdc}(8, 4)[/tex]
[tex]=\text{mdc}(4, 8-4)=\text{mdc}(4, 4)=\text{mdc}(4, 4-4)=\text{mdc}(4, 0)=4[/tex]
b) [tex]\text{mdc}(26, 28)[/tex]
[tex]\text{mdc}(26, 28)=\text{mdc}(26, 28-26)=\text{mdc}(26, 2)=2[/tex]
c) [tex]\text{mdc}(25, 100)[/tex]
[tex]\text{mdc}(25, 100)=\text{mdc}(25, 100 - 25)=\text{mdc}(25, 75)=\text{mdc}(25, 75-25)[/tex]
[tex]\text{mdc}(25, 50)=\text{mdc}(25, 50-25)=\text{mdc}(25, 25)=25[/tex]
d) [tex]\text{mdc}(12, 72)[/tex]
[tex]\text{mdc}(12, 72)=\text{mdc}(12, 72-12\times6)=\text{mdc}(12, 72-72)=\text{mdc}(12, 0)=12[/tex]
e) [tex]\text{mdc}(7, 16)[/tex]
[tex]\text{mdc}(7, 16)=\text{mdc}(7, 16-7\times2)=\text{mdc}(7, 16-14)=\text{mdc}(7,2)[/tex]
[tex]=\text{mdc}(2, 7-2\times3)=\text{mdc}(2, 7-6)=\text{mdc}(2, 1)=1[/tex]