Resposta :

Diogolac

[tex]sendo\ a1,a2,a3:\ (x,\ 2x,\ x^2)\\\\q=\frac{a_2}{a_1}=\frac{2x}{x}=>q=2\\\\e\ proprorcionalmente\\\\ \frac{a_2}{a_1}=\frac{a_3}{a_2}=>\frac{2x}{x}=\frac{x^2}{2x}\\\\ \frac{2x}{x}=\frac{x.x}{2x} (simplifica\ x\ nas\ divisoes)\\\\ \*x=4[/tex]

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