Resposta :
Resposta:
[tex]f'(x) = 2-\frac{7}{3x^{2} }[/tex]
Explicação passo a passo:
[tex]f(x) = 2x+\frac{7}{3x} -9\\[/tex]
[tex]f'(x) = 2+\frac{7}{3}.(\frac{1}{x} )'\\\\f'(x) = 2+\frac{7}{3} .(x^{-1} )'\\\\f'(x) = 2+\frac{7}{3} .(-1x^{-2} )\\\\f'(x) = 2-\frac{7}{3x^{2} }[/tex]