Resposta :

carloseng
[tex] 8x^2-6x=0 [/tex]

x(8x-6)=0    ..... x=0 ou 8x-6=0 ... x=6/8=3/4

confere?
gabyin
8x²-6x= 0

[tex]x= \frac {-b + \sqrt {b^{2}-4ac}} {2a} \\ x= \frac {6 + \sqrt {(-6)^{2}-4(8)(0)}} {2(8)} \\ x= \frac {6 + \sqrt {36}} {16} \\ x= \frac {6 + 6} {16}= \frac {3} {4} [/tex]
ou: 

[tex]x= \frac {-b - \sqrt {b^{2}-4ac}} {2a} \\ x= \frac {6 - \sqrt {(-6)^{2}-4(8)(0)}} {2(8)} \\ x= \frac {6 - \sqrt {36}} {16} \\ x= \frac {6 - 6} {16}= 0[/tex]

x= 6 ou x= 0

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