Resposta :
Se entendi o enunciado...
[tex]a^2b-ab^2=\\\\ab(a-b)=\\\\\frac{-3}{2}\cdot\frac{2}{3}(\frac{-3}{2}-\frac{2}{3})=\\\\\frac{-6}{6}(\frac{-3\cdot3-2\cdot2}{2\cdot3})=\\\\-1(\frac{-9-4}{6})=\\\\\boxed{\frac{13}{6}}[/tex]
[tex]a^2b-ab^2=\\\\ab(a-b)=\\\\\frac{-3}{2}\cdot\frac{2}{3}(\frac{-3}{2}-\frac{2}{3})=\\\\\frac{-6}{6}(\frac{-3\cdot3-2\cdot2}{2\cdot3})=\\\\-1(\frac{-9-4}{6})=\\\\\boxed{\frac{13}{6}}[/tex]