Resposta :

MATHSPHIS
[tex] \sqrt{x} =6-x \\ ( \sqrt{x} )^2=(6-x)^2 = \\ x=36-12x+x^2 \\ \boxed{x^2-13x+36=0} \\ \\ \Delta=(-13)^2-4.1.36=169-144=25 \\ x_1=\frac{13-5}{2}=4 \\ \\ x_2=\frac{13+5}{2}=9 \\ \\ \boxed{S=\{4,9 \}} [/tex]

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