Resposta :

Calcule:
a) Z1+z2+z3=
(1+3i)+(5-4i)+(-2i)
1+5+0 +(3i-4i-2i) =
= 6-3i


b) (1+3i)*(5-4i)*(-2i)=22-34i
3478elc
a) 1+ 3i + 5 - 41 - 2i = 1+5-41+3i-2i = - 35 + i 

b) -2i(1+3i)(5-4i)

    -2i(1+3i)= - 2i -6i^2 = - 2i - 6(-1) ==> - 2i + 6

 (5-4i)(-2i+6)= -10i +30 +8i^2-24i 

 -10i +30 + 8(-1) - 24i ==> -10i +30 - 8 - 24i
     
 + 22 - 34i

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