Resposta :
[tex](\frac{8}{125})^{2x-1}=(\frac{25}{4})^{2x}\rightarrow (\frac{2^3}{5^3})^{2x-1}=(\frac{5^2}{2^2})^{2x} \\\\
(\frac{2}{5})^{3(2x-1)}=(\frac{5}{2})^{2.2x} \\
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(\frac{2}{5})^{6x-3}=[(\frac{2}{5})^{-1}]^{4x} \\
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(\frac{2}{5})^{6x-3}=(\frac{2}{5})^{-4x} \rightarrow 6x-3=-4x \\
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\boxed{10x=3 \rightarrowx=\frac{3}{10}}[/tex]