Resposta :
Basta calcular as raízes da equação:
[tex]2x^2+5x+2=0 \\ \Delta=5^2-4.2.2=25-16=9 \\ x=\frac{-5+-\sqrt{16}}{2.2}=\frac{-5+-3}{4} \\ x_1=-2 \\ x_1=-\frac{1}{2} \\ \\ \boxed{2x^2+5x+2=2(x+2)(x+\frac{1}{2})}[/tex]
[tex]2x^2+5x+2=0 \\ \Delta=5^2-4.2.2=25-16=9 \\ x=\frac{-5+-\sqrt{16}}{2.2}=\frac{-5+-3}{4} \\ x_1=-2 \\ x_1=-\frac{1}{2} \\ \\ \boxed{2x^2+5x+2=2(x+2)(x+\frac{1}{2})}[/tex]