Resposta :
Q1+Q2 =0 -- Q1 = - Q2
Q= m.c /\T
m.c./\T = - (m . c ./\T (Al) )
330 . 1 . ( 20 - 19) = - (50 . 0,22 . ( 20 - T(al) )
330= - (11. ( 20 - T (Al) )
330 =- 220 + 11T
-220 +11T = 330
11T = 330 + 220
11T = 550
T= 550/11
T(al) = 50 ° C
Q= m.c /\T
m.c./\T = - (m . c ./\T (Al) )
330 . 1 . ( 20 - 19) = - (50 . 0,22 . ( 20 - T(al) )
330= - (11. ( 20 - T (Al) )
330 =- 220 + 11T
-220 +11T = 330
11T = 330 + 220
11T = 550
T= 550/11
T(al) = 50 ° C