se x.y=40 e x+2y=55 entao o valor de x²y + 2xy² e
Olá, Gil.
[tex]\begin{cases}xy=40\\x+2y=55 \end{cases} \\\\\\ \underbrace{xy}_{=40}\underbrace{(x+2y)}_{=55}=x^2y+2xy^2 \Rightarrow x^2y+2xy^2=40 \cdot 55\\\\ \\ \therefore \boxed{x^2y+2xy^2=2200}[/tex]
