Resposta :
Temos que:
[tex]3\text{x}^2+5\text{x}-2=0[/tex]
[tex]\text{x}=\dfrac{-5\pm\sqrt{5^2-4\cdot3\cdot(-2)}}{2\cdot3}=\dfrac{-5\pm7}{6}[/tex]
Logo, as raízes são:
[tex]\text{x}'=\dfrac{-5+7}{6}=\dfrac{1}{3}[/tex]
[tex]\text{x}"=\dfrac{-5-7}{6}=-2[/tex]
Desta maneira, [tex]\text{S}=\{-2, \frac{1}{3}\}[/tex]
