Resposta :

[tex]a) d_{AB}=\sqrt{(2-0)^2+(3-2)^2}=\\ \sqrt{2^2+1^2}=\sqrt{4+1}=\sqrt5[/tex]

[tex]b) d_{RS}=\sqrt{(0+2)^2+(2-2)^2}=\\ \sqrt{2^2+0^2}=\sqrt{4+0}=\sqrt4=2[/tex]

[tex]c) d_{MN}=\sqrt{(-2-2)^2+(-2-2)^2}=\\ \sqrt{(-4)^2+(-4)^2}=\sqrt{16+16}=\sqrt{32}=4\sqrt2[/tex]

[tex]d) d_{OP}=\sqrt{(-4-4)^2+(-3-3)^2}=\\ \sqrt{(-8)^2+(-8)^2}=\sqrt{64+64}=\sqrt{128}=8\sqrt2[/tex]

[tex]e) d_{XY}=\sqrt{(0-0)^2+(0-0)^2}=\\ \sqrt{0^2+0^2}=\sqrt{0+0}=\sqrt0=0[/tex]

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